Games on June 25, 1978

The games of June 25, 1978

The schedule for June 25, 1978 lists 17 games. The most lopsided result was the Texas Rangers' 7-0 win over the California Angels. The highest-scoring game ended 10-8, the Seattle Mariners over the Milwaukee Brewers. Shutouts: the Pittsburgh Pirates over the New York Mets (4-0). One-run games: the Toronto Blue Jays 2-1 over the Cleveland Indians, the Cleveland Indians 3-2 over the Toronto Blue Jays, and the Cincinnati Reds 5-4 over the Los Angeles Dodgers. Elsewhere, the Boston Red Sox beat the Baltimore Orioles 4-1, the Minnesota Twins beat the Chicago White Sox 8-5, the Chicago White Sox fell to the Minnesota Twins, 9-6, the New York Yankees beat the Detroit Tigers 4-2, the Oakland Athletics beat the Kansas City Royals 6-3, the Chicago Cubs fell to the Philadelphia Phillies, 4-2, the San Diego Padres topped the Houston Astros 6-1, the San Diego Padres beat the Houston Astros 7-4, the Atlanta Braves fell to the San Francisco Giants, 9-3, and the Atlanta Braves topped the San Francisco Giants 8-4. The Minnesota Twins and the Chicago White Sox, the Toronto Blue Jays and the Cleveland Indians, and the Houston Astros and the San Diego Padres each met twice, as doubleheaders. Only final scores are available for this date. Neighboring dates are one click away: the previous game day, Jun 24, 1978 and the next, Jun 26, 1978. The 1978 season page has the standings and leaders for the year.