Games on September 4, 1978

The games of September 4, 1978

18 games were played on September 4, 1978, according to Retrosheet. The widest margin belonged to the New York Yankees, 9-1 winners over the Detroit Tigers. The highest-scoring game ended 8-7, the California Angels over the Texas Rangers. Shutouts: the Milwaukee Brewers over the Seattle Mariners (5-0) and the Pittsburgh Pirates over the New York Mets (7-0). Decided by a single run were the Montreal Expos 6-5 over the Chicago Cubs, the Los Angeles Dodgers 5-4 over the San Francisco Giants, the Seattle Mariners 4-3 over the Milwaukee Brewers, and the Minnesota Twins 2-1 over the Chicago White Sox. The rest of the slate: the Atlanta Braves fell to the San Diego Padres, 8-4, the Baltimore Orioles beat the Boston Red Sox 5-3, the Chicago Cubs fell to the Montreal Expos, 5-3, the Cincinnati Reds beat the Houston Astros 6-3, the Detroit Tigers topped the New York Yankees 5-4, the Kansas City Royals topped the Oakland Athletics 5-3, the New York Mets fell to the Pittsburgh Pirates, 7-4, the St. Louis Cardinals beat the Philadelphia Phillies 3-2, the St. Louis Cardinals fell to the Philadelphia Phillies, 10-2, and the Toronto Blue Jays fell to the Cleveland Indians, 5-4. Doubleheaders on the date: the Montreal Expos and the Chicago Cubs, the Seattle Mariners and the Milwaukee Brewers, and the Detroit Tigers and the New York Yankees. None of these games has a full box score on the site, so the list gives the final scores. Neighboring dates are one click away: the previous game day, Sep 3, 1978 and the next, Sep 5, 1978. The 1978 season page has the standings and leaders for the year.