Games on May 8, 1990

The games of May 8, 1990

On May 8, 1990, 12 games went into the books. The widest margin belonged to the Montreal Expos, 9-1 winners over the Los Angeles Dodgers. The highest-scoring game ended 10-8, the Chicago Cubs over the Atlanta Braves. The day's shutouts were the California Angels over the Baltimore Orioles (6-0) and the Oakland Athletics over the New York Yankees (5-0). Decided by a single run were the Houston Astros 3-2 over the Philadelphia Phillies, the Minnesota Twins 6-5 over the Cleveland Indians, and the Seattle Mariners 2-1 over the Boston Red Sox. Elsewhere, the Detroit Tigers fell to the Milwaukee Brewers, 7-5, the New York Mets topped the San Francisco Giants 4-1, the Pittsburgh Pirates topped the San Diego Padres 10-2, the Texas Rangers fell to the Kansas City Royals, 10-5, and the Chicago White Sox topped the Toronto Blue Jays 4-1. Only final scores are available for this date. Neighboring dates are one click away: the previous game day, May 7, 1990 and the next, May 9, 1990. For the wider picture, see the 1990 season.