Games on June 3, 1990

The games of June 3, 1990

The schedule for June 3, 1990 lists 13 games. The Boston Red Sox routed the Cleveland Indians 8-2, the widest margin of the day. The day's shutouts were the Cincinnati Reds over the Los Angeles Dodgers (2-0) and the Detroit Tigers over the Seattle Mariners (2-0). One-run games: the Baltimore Orioles 4-3 over the New York Yankees and the Montreal Expos 4-3 over the Pittsburgh Pirates. In the other games, the Minnesota Twins fell to the Chicago White Sox, 5-2, the Kansas City Royals beat the Oakland Athletics 8-2, the New York Mets fell to the Philadelphia Phillies, 8-3, the Atlanta Braves topped the San Diego Padres 4-2, the Houston Astros fell to the San Francisco Giants, 7-3, the Chicago Cubs fell to the St. Louis Cardinals, 7-4, the Texas Rangers fell to the California Angels, 7-4, and the Toronto Blue Jays beat the Milwaukee Brewers 7-4. Only final scores are available for this date. The pager links to the previous game day, Jun 2, 1990 and the next, Jun 4, 1990. For the wider picture, see the 1990 season.