Games on August 4, 1990

The games of August 4, 1990

The schedule for August 4, 1990 lists 13 games. The most lopsided result was the Cleveland Indians' 17-3 win over the New York Yankees. Decided by a single run were the California Angels 6-5 over the Oakland Athletics, the Seattle Mariners 4-3 over the Minnesota Twins, the San Francisco Giants 2-1 over the Los Angeles Dodgers, and the Texas Rangers 3-2 over the Toronto Blue Jays. In the other games, the Kansas City Royals topped the Baltimore Orioles 9-1, the Boston Red Sox beat the Detroit Tigers 3-1, the Chicago Cubs beat the Montreal Expos 10-2, the San Diego Padres topped the Cincinnati Reds 7-3, the Houston Astros beat the Atlanta Braves 6-2, the Milwaukee Brewers fell to the Chicago White Sox, 9-6, the Pittsburgh Pirates topped the Philadelphia Phillies 3-1, and the St. Louis Cardinals beat the New York Mets 7-5. Only final scores are available for this date. The pager links to the previous game day, Aug 3, 1990 and the next, Aug 5, 1990. For the wider picture, see the 1990 season.