Games on September 3, 1990

The games of September 3, 1990

14 games were played on September 3, 1990, according to Retrosheet. The widest margin belonged to the California Angels, 7-0 winners over the New York Yankees. The highest-scoring game ended 9-5, the Minnesota Twins over the Milwaukee Brewers. The day's shutouts were the Detroit Tigers over the Toronto Blue Jays (5-0) and the Minnesota Twins over the Milwaukee Brewers (6-0). Decided by a single run were the Montreal Expos 3-2 over the Chicago Cubs and the San Francisco Giants 5-4 over the San Diego Padres. In the other games, the Atlanta Braves topped the Cincinnati Reds 8-6, the Baltimore Orioles fell to the Seattle Mariners, 6-2, the Oakland Athletics beat the Boston Red Sox 9-5, the Chicago White Sox beat the Kansas City Royals 4-2, the Houston Astros beat the Los Angeles Dodgers 7-3, the Pittsburgh Pirates beat the Philadelphia Phillies 4-1, the New York Mets beat the St. Louis Cardinals 9-3, and the Texas Rangers beat the Cleveland Indians 6-2. The Minnesota Twins and the Milwaukee Brewers met twice, as a doubleheader. The list shows final scores; no game on this date has a full box score here. Neighboring dates are one click away: the previous game day, Sep 2, 1990 and the next, Sep 4, 1990. The 1990 season page has the standings and leaders for the year.