Games on May 28, 1993

14 games

The games of May 28, 1993

14 games were played on May 28, 1993, according to Retrosheet. The widest margin belonged to the Philadelphia Phillies, 15-9 winners over the Colorado Rockies. The day's shutouts were the New York Yankees over the Chicago White Sox (4-0). One-run games: the Florida Marlins 5-4 over the Houston Astros, the Minnesota Twins 7-6 over the Cleveland Indians, the Oakland Athletics 3-2 over the Toronto Blue Jays, and the Seattle Mariners 4-3 over the Detroit Tigers. The rest of the slate: the Atlanta Braves topped the San Francisco Giants 7-4, the Boston Red Sox beat the Texas Rangers 4-1, the California Angels topped the Baltimore Orioles 8-4, the Chicago Cubs beat the Montreal Expos 2-2, the Milwaukee Brewers beat the Kansas City Royals 5-1, the Cincinnati Reds beat the New York Mets 5-2, the Los Angeles Dodgers beat the Pittsburgh Pirates 7-2, and the St. Louis Cardinals topped the San Diego Padres 3-2. The Montreal Expos and the Chicago Cubs played to a 2-2 tie. The list shows final scores; no game on this date has a full box score here. The pager links to the previous game day, May 27, 1993 and the next, May 29, 1993. For the wider picture, see the 1993 season.

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