Games on June 4, 1993

The games of June 4, 1993

The schedule for June 4, 1993 lists 13 games. The Houston Astros routed the New York Mets 7-2, the widest margin of the day. The day's shutouts were the Boston Red Sox over the Chicago White Sox (1-0). The closest finishes were the Baltimore Orioles 6-5 over the Seattle Mariners, the Minnesota Twins 3-2 over the Cleveland Indians, the Kansas City Royals 3-2 over the Milwaukee Brewers, and the Los Angeles Dodgers 5-4 over the Atlanta Braves. The rest of the slate: the California Angels beat the Detroit Tigers 6-3, the Chicago Cubs fell to the Montreal Expos, 3-1, the Philadelphia Phillies fell to the Colorado Rockies, 2-1, the Florida Marlins topped the San Diego Padres 6-2, the San Francisco Giants fell to the Pittsburgh Pirates, 3-2, the New York Yankees fell to the Texas Rangers, 5-3, and the Toronto Blue Jays beat the Oakland Athletics 4-3. Only final scores are available for this date. The pager links to the previous game day, Jun 3, 1993 and the next, Jun 5, 1993. For the wider picture, see the 1993 season.