Games on July 5, 1993

The games of July 5, 1993

15 games were played on July 5, 1993, according to Retrosheet. The Minnesota Twins routed the Detroit Tigers 13-3, the widest margin of the day. Runs came easiest when the San Diego Padres beat the New York Mets 12-7. Decided by a single run were the Boston Red Sox 4-3 over the California Angels, the Texas Rangers 5-4 over the Milwaukee Brewers, the Oakland Athletics 6-5 over the Cleveland Indians, and the Chicago White Sox 4-3 over the Toronto Blue Jays. Elsewhere, the Atlanta Braves topped the Florida Marlins 9-7, the Pittsburgh Pirates fell to the Cincinnati Reds, 6-4, the Chicago Cubs topped the Colorado Rockies 10-1, the Houston Astros fell to the St. Louis Cardinals, 10-4, the Baltimore Orioles fell to the Kansas City Royals, 7-1, the San Francisco Giants topped the Montreal Expos 10-4, the Cleveland Indians beat the Oakland Athletics 6-2, the Los Angeles Dodgers fell to the Philadelphia Phillies, 9-5, and the New York Yankees beat the Seattle Mariners 6-3. The Cleveland Indians and the Oakland Athletics met twice, as a doubleheader. The list shows final scores; no game on this date has a full box score here. The pager links to the previous game day, Jul 4, 1993 and the next, Jul 6, 1993. For the wider picture, see the 1993 season.