Games on July 8, 1993

The games of July 8, 1993

14 games were played on July 8, 1993, according to Retrosheet. The Milwaukee Brewers routed the Minnesota Twins 15-3, the widest margin of the day. The highest-scoring game ended 11-9, the Boston Red Sox over the Oakland Athletics. Decided by a single run were the California Angels 4-3 over the New York Yankees, the Colorado Rockies 3-2 over the Florida Marlins, the Kansas City Royals 6-5 over the Detroit Tigers, and the Montreal Expos 5-4 over the San Diego Padres. The rest of the slate: the Chicago White Sox topped the Baltimore Orioles 12-5, the Chicago Cubs fell to the Cincinnati Reds, 7-3, the Houston Astros topped the Pittsburgh Pirates 10-4, the Los Angeles Dodgers beat the New York Mets 11-8, the Los Angeles Dodgers fell to the New York Mets, 6-3, the Philadelphia Phillies fell to the San Francisco Giants, 13-2, the St. Louis Cardinals beat the Atlanta Braves 7-1, and the Texas Rangers topped the Toronto Blue Jays 6-1. The Los Angeles Dodgers and the New York Mets met twice, as a doubleheader. Only final scores are available for this date. The pager links to the previous game day, Jul 7, 1993 and the next, Jul 9, 1993. The 1993 season page has the standings and leaders for the year.