Games on July 18, 1993

The games of July 18, 1993

The schedule for July 18, 1993 lists 14 games. The widest margin belonged to the Chicago Cubs, 12-2 winners over the Colorado Rockies. The highest-scoring game ended 13-6, the New York Yankees over the Oakland Athletics. The day's shutouts were the Atlanta Braves over the Pittsburgh Pirates (2-0) and the Detroit Tigers over the Texas Rangers (2-0). Decided by a single run were the Boston Red Sox 7-6 over the Seattle Mariners, the Cleveland Indians 2-1 over the California Angels, the Los Angeles Dodgers 2-1 over the Montreal Expos, and the St. Louis Cardinals 7-6 over the Houston Astros. In the other games, the Minnesota Twins fell to the Baltimore Orioles, 7-2, the Cincinnati Reds beat the Florida Marlins 5-3, the Chicago White Sox topped the Milwaukee Brewers 3-1, the Philadelphia Phillies beat the San Diego Padres 6-3, the New York Mets topped the San Francisco Giants 12-6, and the Toronto Blue Jays beat the Kansas City Royals 4-3. Only final scores are available for this date. Neighboring dates are one click away: the previous game day, Jul 17, 1993 and the next, Jul 19, 1993. The 1993 season page has the standings and leaders for the year.