Games on August 8, 1993

The games of August 8, 1993

14 games were played on August 8, 1993, according to Retrosheet. The Texas Rangers routed the Seattle Mariners 7-1, the widest margin of the day. Runs came easiest when the New York Yankees beat the Minnesota Twins 8-6. Decided by a single run were the Atlanta Braves 3-2 over the Montreal Expos, the Baltimore Orioles 7-6 over the Cleveland Indians, the California Angels 2-1 over the Chicago White Sox, and the Florida Marlins 6-5 over the Philadelphia Phillies. In the other games, the Detroit Tigers topped the Boston Red Sox 5-1, the Oakland Athletics fell to the Kansas City Royals, 4-3, the Los Angeles Dodgers fell to the Cincinnati Reds, 8-5, the Pittsburgh Pirates topped the New York Mets 3-2, the Colorado Rockies beat the San Diego Padres 5-2, the San Francisco Giants fell to the Houston Astros, 4-1, the Chicago Cubs beat the St. Louis Cardinals 2-1, and the Milwaukee Brewers beat the Toronto Blue Jays 5-2. Only final scores are available for this date. Neighboring dates are one click away: the previous game day, Aug 7, 1993 and the next, Aug 9, 1993. For the wider picture, see the 1993 season.