Games on August 14, 1993

15 games

The games of August 14, 1993

The schedule for August 14, 1993 lists 15 games. The widest margin belonged to the Houston Astros, 9-0 winners over the Colorado Rockies. Runs came easiest when the New York Mets beat the Philadelphia Phillies 9-5. A shutout went on the board for the St. Louis Cardinals over the Montreal Expos (2-0). Decided by a single run were the Chicago Cubs 3-2 over the San Francisco Giants and the Los Angeles Dodgers 4-3 over the San Diego Padres. The rest of the slate: the Toronto Blue Jays topped the Boston Red Sox 5-2, the Chicago White Sox topped the Kansas City Royals 4-1, the Cincinnati Reds fell to the Atlanta Braves, 4-2, the Cleveland Indians topped the Texas Rangers 8-5, the Milwaukee Brewers fell to the Detroit Tigers, 5-1, the New York Yankees beat the Baltimore Orioles 4-2, the Minnesota Twins topped the Oakland Athletics 5-1, the Oakland Athletics fell to the Minnesota Twins, 6-2, the Florida Marlins topped the Pittsburgh Pirates 8-3, and the California Angels fell to the Seattle Mariners, 7-2. The Minnesota Twins and the Oakland Athletics met twice, as a doubleheader. The list shows final scores; no game on this date has a full box score here. The pager links to the previous game day, Aug 13, 1993 and the next, Aug 15, 1993. The 1993 season page has the standings and leaders for the year.

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