Games on August 17, 1993

The games of August 17, 1993

The schedule for August 17, 1993 lists 16 games. The most lopsided result was the New York Yankees' 11-4 win over the Texas Rangers. Runs came easiest when the Philadelphia Phillies beat the Colorado Rockies 10-7. Shutouts: the Cincinnati Reds over the New York Mets (6-0) and the Houston Astros over the Florida Marlins (4-0). Decided by a single run were the Atlanta Braves 3-2 over the Los Angeles Dodgers, the Chicago White Sox 3-2 over the Boston Red Sox, the Kansas City Royals 3-2 over the Minnesota Twins, and the Texas Rangers 3-2 over the New York Yankees. Elsewhere, the Detroit Tigers beat the California Angels 9-3, the Montreal Expos fell to the Chicago Cubs, 7-2, the Montreal Expos topped the Chicago Cubs 6-4, the Toronto Blue Jays beat the Cleveland Indians 6-4, the Milwaukee Brewers fell to the Oakland Athletics, 6-3, the Pittsburgh Pirates topped the San Francisco Giants 10-3, the Seattle Mariners topped the Baltimore Orioles 5-3, and the St. Louis Cardinals beat the San Diego Padres 8-4. Doubleheaders on the date: the Montreal Expos and the Chicago Cubs and the Texas Rangers and the New York Yankees. The list shows final scores; no game on this date has a full box score here. Neighboring dates are one click away: the previous game day, Aug 16, 1993 and the next, Aug 18, 1993. The 1993 season page has the standings and leaders for the year.