Games on September 8, 1993

The games of September 8, 1993

On September 8, 1993, 13 games went into the books. The widest margin belonged to the Chicago White Sox, 8-1 winners over the Boston Red Sox. Runs came easiest when the Cleveland Indians beat the Minnesota Twins 15-8. The closest finishes were the Milwaukee Brewers 2-1 over the Kansas City Royals, the San Diego Padres 3-2 over the Florida Marlins, and the Oakland Athletics 2-1 over the Toronto Blue Jays. Elsewhere, the Baltimore Orioles topped the Seattle Mariners 6-3, the Cincinnati Reds beat the St. Louis Cardinals 6-2, the Detroit Tigers topped the California Angels 4-2, the New York Mets fell to the Houston Astros, 7-1, the Los Angeles Dodgers fell to the Atlanta Braves, 8-2, the Colorado Rockies fell to the Montreal Expos, 6-1, the Philadelphia Phillies fell to the Chicago Cubs, 8-5, and the Texas Rangers beat the New York Yankees 4-1. Only final scores are available for this date. Neighboring dates are one click away: the previous game day, Sep 7, 1993 and the next, Sep 9, 1993. The 1993 season page has the standings and leaders for the year.