Games on September 10, 1993

The games of September 10, 1993

Retrosheet's records show 16 games on September 10, 1993. The Seattle Mariners routed the Milwaukee Brewers 10-3, the widest margin of the day. The highest-scoring game ended 12-10, the Chicago Cubs over the New York Mets. Shutouts: the Detroit Tigers over the Chicago White Sox (4-0). One-run games: the Boston Red Sox 5-4 over the Cleveland Indians, the Kansas City Royals 6-5 over the New York Yankees, the Florida Marlins 2-1 over the Los Angeles Dodgers, and the Montreal Expos 4-3 over the Cincinnati Reds. Elsewhere, the Baltimore Orioles fell to the Oakland Athletics, 12-9, the Cleveland Indians beat the Boston Red Sox 7-4, the Houston Astros fell to the Philadelphia Phillies, 6-2, the Pittsburgh Pirates fell to the Colorado Rockies, 9-8, the San Diego Padres fell to the Atlanta Braves, 3-2, the San Francisco Giants fell to the St. Louis Cardinals, 6-2, the Texas Rangers beat the Minnesota Twins 4-3, the Texas Rangers beat the Minnesota Twins 3-2, and the California Angels fell to the Toronto Blue Jays, 10-4. The Boston Red Sox and the Cleveland Indians and the Minnesota Twins and the Texas Rangers each met twice, as doubleheaders. Only final scores are available for this date. Neighboring dates are one click away: the previous game day, Sep 9, 1993 and the next, Sep 11, 1993. The 1993 season page has the standings and leaders for the year.