Games on September 18, 1993

The games of September 18, 1993

14 games were played on September 18, 1993, according to Retrosheet. The widest margin belonged to the Los Angeles Dodgers, 9-0 winners over the Colorado Rockies. Runs came easiest when the Detroit Tigers beat the Cleveland Indians 7-6. The day's shutouts were the Milwaukee Brewers over the Baltimore Orioles (3-0) and the Kansas City Royals over the Seattle Mariners (1-0). One-run games: the New York Mets 3-2 over the Atlanta Braves, the Chicago Cubs 6-5 over the Florida Marlins, the Philadelphia Phillies 5-4 over the Montreal Expos, and the New York Yankees 4-3 over the Boston Red Sox. In the other games, the California Angels fell to the Texas Rangers, 9-2, the San Francisco Giants beat the Cincinnati Reds 6-1, the San Diego Padres fell to the Houston Astros, 4-2, the Minnesota Twins fell to the Toronto Blue Jays, 5-1, the Oakland Athletics topped the Chicago White Sox 3-2, and the St. Louis Cardinals beat the Pittsburgh Pirates 8-1. None of these games has a full box score on the site, so the list gives the final scores. Neighboring dates are one click away: the previous game day, Sep 17, 1993 and the next, Sep 19, 1993. The 1993 season page has the standings and leaders for the year.