Games on August 7, 1996

The games of August 7, 1996

The schedule for August 7, 1996 lists 14 games. The most lopsided result was the Atlanta Braves' 14-1 win over the Philadelphia Phillies. The highest-scoring game ended 13-5, the Montreal Expos over the Houston Astros. Shutouts: the Boston Red Sox over the Toronto Blue Jays (8-0), the Minnesota Twins over the California Angels (4-0), and the Kansas City Royals over the Oakland Athletics (7-0). The closest finishes were the Cleveland Indians 5-4 over the Seattle Mariners and the St. Louis Cardinals 1-0 over the San Diego Padres. In the other games, the New York Mets beat the Chicago Cubs 11-7, the Colorado Rockies topped the Florida Marlins 12-5, the Detroit Tigers topped the Texas Rangers 4-2, the Baltimore Orioles topped the Milwaukee Brewers 12-2, the Chicago White Sox beat the New York Yankees 8-4, the Pittsburgh Pirates beat the Los Angeles Dodgers 12-2, and the San Francisco Giants beat the Cincinnati Reds 9-2. Only final scores are available for this date. The pager links to the previous game day, Aug 6, 1996 and the next, Aug 8, 1996. The 1996 season page has the standings and leaders for the year.