Games on September 7, 1990

The games of September 7, 1990

On September 7, 1990, 13 games went into the books. The most lopsided result was the Oakland Athletics' 7-1 win over the New York Yankees. The highest-scoring game ended 9-4, the Texas Rangers over the Kansas City Royals. Shutouts: the Minnesota Twins over the Cleveland Indians (2-0). The closest finishes were the Boston Red Sox 5-4 over the Seattle Mariners, the St. Louis Cardinals 4-3 over the Chicago Cubs, the Milwaukee Brewers 6-5 over the Detroit Tigers, and the Houston Astros 2-1 over the San Francisco Giants. In the other games, the Baltimore Orioles topped the California Angels 6-2, the Los Angeles Dodgers beat the Cincinnati Reds 3-1, the Philadelphia Phillies topped the New York Mets 4-1, the Montreal Expos beat the Pittsburgh Pirates 4-1, the Atlanta Braves beat the San Diego Padres 4-1, and the Toronto Blue Jays topped the Chicago White Sox 3-1. The list shows final scores; no game on this date has a full box score here. Neighboring dates are one click away: the previous game day, Sep 6, 1990 and the next, Sep 8, 1990. For the wider picture, see the 1990 season.