Games on September 8, 1990

13 games

The games of September 8, 1990

The schedule for September 8, 1990 lists 13 games. The widest margin belonged to the New York Mets, 12-2 winners over the Philadelphia Phillies. The highest-scoring game ended 11-5, the Atlanta Braves over the San Diego Padres. A shutout went on the board for the Toronto Blue Jays over the Chicago White Sox (3-0). The closest finishes were the Baltimore Orioles 5-4 over the California Angels, the Chicago Cubs 5-4 over the St. Louis Cardinals, the San Francisco Giants 2-1 over the Houston Astros, and the Texas Rangers 2-1 over the Kansas City Royals. In the other games, the Boston Red Sox beat the Seattle Mariners 10-2, the Los Angeles Dodgers fell to the Cincinnati Reds, 8-4, the Milwaukee Brewers topped the Detroit Tigers 5-2, the Cleveland Indians fell to the Minnesota Twins, 6-1, the New York Yankees fell to the Oakland Athletics, 5-2, and the Pittsburgh Pirates beat the Montreal Expos 6-1. The list shows final scores; no game on this date has a full box score here. Neighboring dates are one click away: the previous game day, Sep 7, 1990 and the next, Sep 9, 1990. The 1990 season page has the standings and leaders for the year.

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